The largest number which divides 285 and 1249
Splet19. jul. 2010 · What is required is the largest number n such that: 285 = jn + 9. 1249 = kn + 7. So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276. … SpletIn recreational mathematics, a repunit is a number like 11, 111, or 1111 that contains only the digit 1 — a more specific type of repdigit.The term stands for repeated unit and was coined in 1966 by Albert H. Beiler in his book Recreations in the Theory of Numbers.. A repunit prime is a repunit that is also a prime number.Primes that are repunits in base-2 …
The largest number which divides 285 and 1249
Did you know?
SpletTherefore, the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Explain math question Mathematics is the study of numbers, shapes, and patterns. SpletWe need to find the greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively. The required number when divides 285 and 1249, leaves remainder 9 and 7, …
Splet19. jul. 2010 · What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242... SpletHence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Find the greatest number which divides 285 and 1249 If the …
SpletFind the largest number which exactly divides 285 and 1249 - Apps can be a great way to help learners with their math. Let's try the best Find the largest. ... Therefore, the greatest number which divides 285 and 1249 leaving remainders 9 and 7 is 138. Related Questions. Find the largest number which divides 615 and SpletRelated Questions. Find the largest number which divides 615 and Do my homework for me. Main site navigation. Math Textbook. Solve Now. Find the greatest number which divides 285 and. Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively. The new numbers after subtracting remainders are: 285-9 = 276. ...
Splet43 is a Heegner number. 43 is the largest prime which divides the order of the Janko group J 4. 43 is a repdigit in base 6 (111). 43 is the number of triangles inside the Sri Yantra. 43 is the largest natural number that is not an (original) McNugget number. 43 is the smallest prime number expressible as the sum of 2, 3, 4, or 5 different primes:
SpletThe required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. Was this answer helpful? upvote 0. Expert instructors will give you an answer in real-time; Deal with mathematic; Track Improvement; ... Find the largest number which divides 615 and coach lawsonSpletWhat is the greatest number which divides 285 and 1249 and leaves a remainder of 5 and 7? Solution: 285–5 = 280. 1249–7 = 1242. Factors of. 280 = 2x2x2x5x7. 1242 = … coach laylaSplet04. okt. 2024 · Therefore, the greatest number which divides 285 and 1249 leaving the remainder 9 and 7 respectively is 138, option D). So, the correct answer is “Option D”. Note: A factor is a number that divides another number without leaving any remainder. coach lawrenceSpletTherefore, the greatest number which divides 285 and 1249 leaving remainders 9 and 7 is 138. Related Questions. Find the largest number which divides 615 and Decide mathematic tasks Experts will give you an answer in real-time Top Teachers Do mathematic equations Find the greatest number which divides 285 and 1249 leaving ... calgary school board spring breakSpletThe required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. calgary school calendar 2021 2022SpletFind the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively. Determine math questions. To determine what the math problem is, you will need to take a close look at the information given and use your problem-solving skills. Once you have determined what the problem is, you can begin to work on finding the solution. coach layoffSplet25. jan. 2024 · Best answer The required number when divides 445, 572 and 699 leaves remainders 4, 5 and 6 This means 445 – 4 = 441, 572 – 5 = 561 and 699 – 6 = 693 are completely divisible by the number ∴ The required number = HCF of 441, 567 and 693 First consider 441 and 567 By applying Euclid’s division lemma 567 = 441 × 1 + 126 441 = 126 … calgary school calendar 2022